adjust my code

Hi,
I've created this code to determine the dates for an exam when a
certification must be met within a X number of months or years. The last
deadline date for an exam is the enddate. The marge where one can
schedule his time to study depends on how many exams he must take. So
based on the enddate i calculate backwards to the startdate to get
intervals of when the next examdate should be.
In my testscenario i used 12 months and the number of exams are 4. The
code gave me the results i needed, but when i tried e.g. 18 months the
results are not what i expected. The dates are somewhat correct but
there were too many dates.
Can someone see the error in my code?
declare @.exams int,
@.begindate datetime,
@.enddate datetime,
@.examdate datetime,
@.intervals int,
set @.begindate = '2005-11-23'
set @.enddate = dateadd(mm,12,@.begindate)
set @.exams = 4
set @.intervals = datediff(mm,@.begindate,@.enddate)/@.exams
create table #examdates(id int identity(1,1) , examdate datetime)
--i inserted the enddate as startingpoint, but this could be done
--better, i think
insert into #examdates(examdate)
values(@.enddate)
while (select count(*) from #examdates) <= @.intervals
begin
set @.examdate = (select examdate from #examdates where id in
(select max(id) from #examdates))
insert into #examdates(examdate)
select dateadd(mm,-@.exams,@.examdate) as examdate
end
select examdate from #examdates order by examdateJason
> results are not what i expected. The dates are somewhat correct but
> there were too many dates.
>
What do you want to return if you put 18 months in?
"Jason" <jasonlewis@.hotmail.com> wrote in message
news:eonG0vfEGHA.2040@.TK2MSFTNGP14.phx.gbl...
> Hi,
> I've created this code to determine the dates for an exam when a
> certification must be met within a X number of months or years. The last
> deadline date for an exam is the enddate. The marge where one can schedule
> his time to study depends on how many exams he must take. So based on the
> enddate i calculate backwards to the startdate to get intervals of when
> the next examdate should be.
> In my testscenario i used 12 months and the number of exams are 4. The
> code gave me the results i needed, but when i tried e.g. 18 months the
> results are not what i expected. The dates are somewhat correct but
> there were too many dates.
> Can someone see the error in my code?
> declare @.exams int,
> @.begindate datetime,
> @.enddate datetime,
> @.examdate datetime,
> @.intervals int,
> set @.begindate = '2005-11-23'
> set @.enddate = dateadd(mm,12,@.begindate)
> set @.exams = 4
> set @.intervals = datediff(mm,@.begindate,@.enddate)/@.exams
> create table #examdates(id int identity(1,1) , examdate datetime)
> --i inserted the enddate as startingpoint, but this could be
> done --better, i think
> insert into #examdates(examdate)
> values(@.enddate)
> while (select count(*) from #examdates) <= @.intervals
> begin
> set @.examdate = (select examdate from #examdates where id in
> (select max(id) from #examdates))
> insert into #examdates(examdate)
> select dateadd(mm,-@.exams,@.examdate) as examdate
> end
> select examdate from #examdates order by examdate|||You are creating a variable called intervals which is really the number of
months that you have to take each exam based on the way that you set it.
datediff(mm,@.begindate,@.enddate)/@.exams
So for 12 months this would be 3 but for 18 months it would be 4.5.
You then use this as the loop constraint for adding in your exam dates.
It seems to me like your look constraint should just be the number of exams
that you need to take since you are trying to find a date when to take each
of the exams.
This is the core of your problem. I didn't put any thought into the rest of
the algorithm and how you might be able to accomplish your goal easier.
HTH
Ryan Powers
Clarity Consulting
http://www.claritycon.com
"Jason" wrote:

> Hi,
> I've created this code to determine the dates for an exam when a
> certification must be met within a X number of months or years. The last
> deadline date for an exam is the enddate. The marge where one can
> schedule his time to study depends on how many exams he must take. So
> based on the enddate i calculate backwards to the startdate to get
> intervals of when the next examdate should be.
> In my testscenario i used 12 months and the number of exams are 4. The
> code gave me the results i needed, but when i tried e.g. 18 months the
> results are not what i expected. The dates are somewhat correct but
> there were too many dates.
> Can someone see the error in my code?
> declare @.exams int,
> @.begindate datetime,
> @.enddate datetime,
> @.examdate datetime,
> @.intervals int,
> set @.begindate = '2005-11-23'
> set @.enddate = dateadd(mm,12,@.begindate)
> set @.exams = 4
> set @.intervals = datediff(mm,@.begindate,@.enddate)/@.exams
> create table #examdates(id int identity(1,1) , examdate datetime)
> --i inserted the enddate as startingpoint, but this could be done
> --better, i think
> insert into #examdates(examdate)
> values(@.enddate)
> while (select count(*) from #examdates) <= @.intervals
> begin
> set @.examdate = (select examdate from #examdates where id in
> (select max(id) from #examdates))
> insert into #examdates(examdate)
> select dateadd(mm,-@.exams,@.examdate) as examdate
> end
> select examdate from #examdates order by examdate
>|||Ryan Powers wrote:
> You are creating a variable called intervals which is really the number of
> months that you have to take each exam based on the way that you set it.
> datediff(mm,@.begindate,@.enddate)/@.exams
> So for 12 months this would be 3 but for 18 months it would be 4.5.
> You then use this as the loop constraint for adding in your exam dates.
> It seems to me like your look constraint should just be the number of exam
s
> that you need to take since you are trying to find a date when to take eac
h
> of the exams.
>
> This is the core of your problem. I didn't put any thought into the rest
of
> the algorithm and how you might be able to accomplish your goal easier.
> HTH
>
Hi Ryan,
I want to calculate a date for taking an exam. The intervals are just
the number of months when the next exam must be taken.
Could you point out to me where i should better my code?|||Uri Dimant wrote:
> Jason
>
>
> What do you want to return if you put 18 months in?
>
> "Jason" <jasonlewis@.hotmail.com> wrote in message
> news:eonG0vfEGHA.2040@.TK2MSFTNGP14.phx.gbl...
>
>
>
Hi Uri,
I want to return 4 examdates because the number of exams to be taken are
4, the higher the months the longer someone may study until the next
date occurs.
In case of adding 18 months to the begindate, divide that with the
number of exams, you'll get 4.5 months. So knowing the enddate (is also
the last examdate deadline) i substract the 4.5 months from the enddate
which will give me the examdate before that and so on.
Can you find the mistake i have made in the code?|||Try the following script. I have given some hint about changes made in your
script. Inside the While loop, I have removed the select statement from the
#examdates table. This will enhance performance.
declare @.exams int,
@.begindate datetime,
@.enddate datetime,
@.examdate datetime,
@.intervals int
-- Added script
declare @.NextExamDate datetime, @.LastExamDate datetime
--
set @.begindate = '20051101'
set @.enddate = dateadd(mm,12,@.begindate)
-- Added script
set @.LastExamDate = @.enddate
--
set @.exams = 4
--[replaced with below line] set @.intervals =
datediff(mm,@.begindate,@.enddate)/@.exams
set @.intervals = datediff(dd,@.begindate,@.enddate)/@.exams
--create table #examdates(id int identity(1,1) , examdate datetime)
--i inserted the enddate as startingpoint, but this could be done
--better, i think
insert into #examdates(examdate)
values(@.enddate)
-- While loop script with lots of changes
while @.exams > 1
begin
set @.NextExamDate = dateadd(dd,-@.intervals,@.LastExamDate)
insert into #examdates(examdate) values(@.NextExamDate)
set @.LastExamDate = @.NextExamDate
set @.exams = @.exams -1
end
--
select examdate from #examdates order by examdate
"Jason" wrote:

> Ryan Powers wrote:
> Hi Ryan,
> I want to calculate a date for taking an exam. The intervals are just
> the number of months when the next exam must be taken.
> Could you point out to me where i should better my code?
>|||Sure. You don't need the intervals variable, since you are actually
recalcing it on the fly within the loop. I am going to just keep your base
logic, and show you how you can correct it so it works.
I changed it slightly to find days between exams because I'm thinking that
you can evenly divide the months by the number of exams is not correct. Wha
t
I did will not necessarily give you your last exam on your end date due to
integer math. But, it should be close. We could put in a condition that
checks if we are setting the last date and just set it as the enddate. Let
me know if you need help with that.-
declare @.exams int,
@.begindate datetime,
@.enddate datetime,
@.examdate datetime,
@.intervals int,
@.months int,
@.daysBetweenExams
set @.begindate = '2005-11-23'
set @.exams = 4
set @.months = 12
set @.enddate = dateadd(mm,@.months,@.begindate)
set @.daysBetweenExams = datediff(dd, @.begindate, @.enddate)/@.exams
create table #examdates(id int identity(1,1) , examdate datetime)
set @.examdate = @.begindate
while (select count(*) from #examdates) <= @.exams
begin
SELECT @.examdate = dateadd(dd, @.daysBetweenExams, @.examdate)
insert into #examdates(examdate)
values(@.examdate)
end
select examdate from #examdates order by examdate
--
Ryan Powers
Clarity Consulting
http://www.claritycon.com
"Jason" wrote:

> Ryan Powers wrote:
> Hi Ryan,
> I want to calculate a date for taking an exam. The intervals are just
> the number of months when the next exam must be taken.
> Could you point out to me where i should better my code?
>|||On Thu, 05 Jan 2006 14:28:42 +0100, Jason wrote:

>Hi,
>I've created this code to determine the dates for an exam when a
>certification must be met within a X number of months or years. The last
> deadline date for an exam is the enddate. The marge where one can
>schedule his time to study depends on how many exams he must take. So
>based on the enddate i calculate backwards to the startdate to get
>intervals of when the next examdate should be.
>In my testscenario i used 12 months and the number of exams are 4. The
>code gave me the results i needed, but when i tried e.g. 18 months the
>results are not what i expected. The dates are somewhat correct but
>there were too many dates.
>Can someone see the error in my code?
Hi Jason,
Why not use a set-based query instead of looping?
-- inputs:
DECLARE @.begindate datetime,
@.enddate datetime,
@.exams int
SET @.begindate = '2005-11-23'
SET @.enddate = '2007-05-23'
SET @.exams = 4
-- generate exam dates
--INSERT INTO @.examdate(examdate)
SELECT DATEADD(month,
Number * DATEDIFF(month, @.begindate, @.enddate) / @.exams,
@.begindate)
FROM dbo.Numbers
WHERE Number BETWEEN 1 AND @.exams
Note: this requires the use of a numbers table. See www.aspfaq.com/2516.
Hugo Kornelis, SQL Server MVP|||Hugo Kornelis wrote:
> On Thu, 05 Jan 2006 14:28:42 +0100, Jason wrote:
>
>
> Hi Jason,
> Why not use a set-based query instead of looping?
> -- inputs:
> DECLARE @.begindate datetime,
> @.enddate datetime,
> @.exams int
> SET @.begindate = '2005-11-23'
> SET @.enddate = '2007-05-23'
> SET @.exams = 4
> -- generate exam dates
> --INSERT INTO @.examdate(examdate)
> SELECT DATEADD(month,
> Number * DATEDIFF(month, @.begindate, @.enddate) / @.exams,
> @.begindate)
> FROM dbo.Numbers
> WHERE Number BETWEEN 1 AND @.exams
> Note: this requires the use of a numbers table. See www.aspfaq.com/2516.
>
Hi hugo,
your solution did the job. Thnx!

Adding two dates

I have two fields, Date Purchased (smalldatetime) and warranty in months (integer).

can anyone help me to formulate a query to show the date when the warranty ends, and/or the remaining days/months in the warranty please?

I'm not sure if its doable, but i would really appreciate it if anyone can help me!

Give a look to the DATEADD function in books online; it looks like this:

declare @.example table
( rid integer,
datePurchased smalldatetime,
warranty integer
)

insert into @.example
select 1, '4/8/7', 3 union all
select 2, '5/14/7', 12

select rid,
convert(varchar(10), datePurchased, 101) as datePurchased,
warranty,
dateadd (mm, warranty, datePurchased) as warrantyEndDate,
datediff (day, getdate(), dateadd (mm, warranty, datePurchased)) as daysRemaining,
datediff (mm, getdate(), dateadd (mm, warranty, datePurchased)) as monthsRemaining
from @.example

/*
rid datePurchased warranty warrantyEndDate daysRemaining monthsRemaining
-- - -- - -
1 04/08/2007 3 2007-07-08 00:00:00 45 2
2 05/14/2007 12 2008-05-14 00:00:00 356 12
*/

Adding Default Dates within Reporting Services Admin

Is there any way, within the admin to specify that
yesterday and today for start date and end date. Someone
suggested =Today.AddDays(-1) but I don't think they meant
in the admin. Could you tell me where i am supposed to
apply this default.
Regards,
BryanIf by admin you mean through the report manager, then there is no way. The
report manager does not support entering expressions.
--
-Daniel
This posting is provided "AS IS" with no warranties, and confers no rights.
"bmurtha" <anonymous@.discussions.microsoft.com> wrote in message
news:9f5001c4791a$bf4e8040$a301280a@.phx.gbl...
> Is there any way, within the admin to specify that
> yesterday and today for start date and end date. Someone
> suggested =Today.AddDays(-1) but I don't think they meant
> in the admin. Could you tell me where i am supposed to
> apply this default.
> Regards,
> Bryan

Adding dates to a matrix

Hi,
I have a matrix showing transactions between two dates. I want to show those
dates to the users in columns. Let's say the user chose all transactions
between 1/1/03 and 30/10/03. How can I add columns to represent all months in
that period (or days, years, etc.)?
ThanksHi G,
If you don't have any data rows for a certain month/day, then it will not
show up in the matrix grouping. To ensure that certain groups/data values
are always present, you will need an outer join in your dataset query e.g.
in case of months with a simple table that just has 12 rows with one column
and values from 1 to 12.
Using parameters makes it a little bit more complex. You could either
integrate modify the outer join query to select only subsets of the table
(and achieve better performance), or you apply filters on the matrix
groupings in RS.
Details on how to use outer joins are available here:
http://msdn.microsoft.com/library/default.asp?url=/library/en-us/acdata/ac_8_qd_09_0zqr.asp
http://msdn.microsoft.com/library/en-us/acdata/ac_8_qd_09_1h6b.asp
HTH,
Robert
--
This posting is provided "AS IS" with no warranties, and confers no rights.
"G" <G@.discussions.microsoft.com> wrote in message
news:A1D100A0-E235-4EEC-B4F5-22AA80C170B4@.microsoft.com...
> Hi,
> I have a matrix showing transactions between two dates. I want to show
those
> dates to the users in columns. Let's say the user chose all transactions
> between 1/1/03 and 30/10/03. How can I add columns to represent all months
in
> that period (or days, years, etc.)?
> Thanks

Adding dates in SQL

I am trying to pull only records that are greater than 1 month prior to today's date. This is what I have so far...

select *
from MyTable
where eventDateStart > '$Now'
order by eventDateStart

$Now is a variable that pulls in today's date. This sql statement delivers only records that have a eventDateStart greater than today. My problem is I do not know how to make it so it only shows records that are 1 month prior.

Any idea how to do this?Have a look at the DATEDIFF function in SQL Server|||This should do it for you:

SELECT * FROM MyTable
WHERE eventDateStart < DATEADD(m, -1, GETDATE())

Cheers

Gary|||Ok, this is frustrating, I can not get the DATEADD function to work for some reason. This is exactly what I want..

select *
from MyTable
where eventDateStart > DATEADD (m,-1,'2004/12/26')

This "SHOULD" return all the events that have a start date greater than November 26,2004 right? Am I crazy or something? If I get rid of the dateadd function and just have this where clause...

where eventDateStart > '2004/12/26'

it returns exactly what it should...all events that have a start date later than the 12/26/2004. But as soon as I try to DATEADD it returns zero rows. What the heck am I doing wrong|||Hi again,

Sorry I screwed up the first time as I should have said:
eventDateStart > DATEADD(m, -1, GETDATE())
instead of
eventDaytStart < DATEADD(m, -1, GETDATE())

In any case I checked your hardcoded version (SELECT DATEADD (m,-1,'2004/12/26') )and my version (SELECT DATEADD(m, -1, GETDATE())) in query analyzer and both give me the expected results.

I don't know if this is typo on your part but your DATEADD version will produce a comparison date of 2004/11/26 not 2004/12/26, so you are likely to get different results. Try it in query analyzer making sure you are using a dateadd that will be the same date as your hardcoded value and see what happens.

If that failds post the entire query/procedure and I'll look at it again because you're right, there is no reason why this should be difficult.

Cheers

Gary

Adding dates giving blank or incorrect date

My report has a finishdate column which is grouped into week intervals, Im trying to run the following formula to get the Saturday(end of the week) based on the finishdate e.g if the finish date is 4/7/2006 which is a Tuesday, I want to find out what the end off week date is - which would be 8/7/2006 (Saturday) and place this into another column.

NumberVar whatday;

whatday = dayofweek({finishdate});
If whatday = 2 then //monday
{finishdate} + 5;
Else whatday = 3 then
{finishdate} + 4;
Else whatday = 4 then
{finishdate} + 3;
Else whatday = 5 then
{finishdate} + 2;
Else whatday = 6 then
{finishdate} + 1;

This is not returning any errors but also it is giving me just a blank output. Also when i run the lines
{finishdate} + 4;
on its own, the dates are adding up correctly

OR

dayofweek({finishdate}) onit owns it returns the correct day off week for the finishdate

when i put variables
NumberVar whatday;

whatday = dayofweek({finishdate});
If whatday = 2 then //monday
{finishdate} + 5;

i get a day returned off 1/1/-4713 or an incorrect dayofweek
I have no idea why this is returned.

I am using Crystal Report 7 and the dateadd() is not available, I dont know why when run with conditions etc such as if and variable declarations, it doesnt return the right date, but when run on its own it works.

Can someone help,

thanksThe common mistake people do with Crystal, is when they forget there are two different syntaxes: Crystal and VB. In your case, I think the problem is in assignment operator. Try whatday := dayofweek({finishdate}); instead of whatday = dayofweek({finishdate}); The latter would return the boolean value as a result of comparision, not assignment.

Adding Date and zero values to non existent dates

Hi,
I have info about my customers and when they place their orders. I am trying
to get a report that will tell me the sum of their orders for each month fo
r
the last 24 months. The problem I'm having is that certain customers don't
have order in every month so I'm only able to query on what's there.
How can I create a table or a view that would return every months in the
last 24 months with the sum of their orders for each month and 0 for months
that had no orders?
Thanks in advance.Read this for some ideas:
http://www.aspfaq.com/show.asp?id=2519
"Frenchie418" <Frenchie418@.discussions.microsoft.com> wrote in message
news:F57924D5-DF9C-46EE-A4B6-B8CFBBBB4026@.microsoft.com...
> Hi,
> I have info about my customers and when they place their orders. I am
> trying
> to get a report that will tell me the sum of their orders for each month
> for
> the last 24 months. The problem I'm having is that certain customers don't
> have order in every month so I'm only able to query on what's there.
> How can I create a table or a view that would return every months in the
> last 24 months with the sum of their orders for each month and 0 for
> months
> that had no orders?
> Thanks in advance.|||Thanks, I think this will help... Merci Beaucoup!
"Raymond D'Anjou" wrote:

> Read this for some ideas:
> http://www.aspfaq.com/show.asp?id=2519
> "Frenchie418" <Frenchie418@.discussions.microsoft.com> wrote in message
> news:F57924D5-DF9C-46EE-A4B6-B8CFBBBB4026@.microsoft.com...
>
>