Hi. Perhaps I am missing something obvious, but I am confused. I can
add a SQL Server 2005 user with this command:
CREATE LOGIN 'AUser' WITH PASSWORD = 'hello', DEFAULT_DATABASE = TEST1
However, I have 100 users to add, and I want to use TRANSACT-SQL to
create the users automatically and pull their initial password info
from a table. I use a cursor to do this, replacing the 'AUser' and
'hello' with variables, for example:
CREATE LOGIN @.usr WITH PASSWORD = @.pwd
I get an Incorrect syntax near '@.usr' error. Somehow this is not the
correct datatype, I would imagine. I used this method with sp_addlogin
in SQL 2000 without a problem.
I've tried declaring @.usr as a varchar or nvarchar without success.
Please offer any suggestions.
Thank you.Seems CREATE LOGIN doesn't accept a variable for one of both those parameters. You can build the
CREATE LOGIN command in a variable and then use dynamic SQL to execute it:
EXEC(@.sql)
--
Tibor Karaszi, SQL Server MVP
http://www.karaszi.com/sqlserver/default.asp
http://www.solidqualitylearning.com/
"Jim Johnson" <easytorememberemailaddress@.gmail.com> wrote in message
news:1166460727.281101.297550@.79g2000cws.googlegroups.com...
> Hi. Perhaps I am missing something obvious, but I am confused. I can
> add a SQL Server 2005 user with this command:
> CREATE LOGIN 'AUser' WITH PASSWORD = 'hello', DEFAULT_DATABASE = TEST1
> However, I have 100 users to add, and I want to use TRANSACT-SQL to
> create the users automatically and pull their initial password info
> from a table. I use a cursor to do this, replacing the 'AUser' and
> 'hello' with variables, for example:
> CREATE LOGIN @.usr WITH PASSWORD = @.pwd
> I get an Incorrect syntax near '@.usr' error. Somehow this is not the
> correct datatype, I would imagine. I used this method with sp_addlogin
> in SQL 2000 without a problem.
> I've tried declaring @.usr as a varchar or nvarchar without success.
> Please offer any suggestions.
> Thank you.
>|||Excellent idea. I was hung up on trying to get it to accept the
variable.
Tibor Karaszi wrote:
> Seems CREATE LOGIN doesn't accept a variable for one of both those parameters. You can build the
> CREATE LOGIN command in a variable and then use dynamic SQL to execute it:
> EXEC(@.sql)
> --
> Tibor Karaszi, SQL Server MVP
> http://www.karaszi.com/sqlserver/default.asp
> http://www.solidqualitylearning.com/
>|||This is a multi-part message in MIME format.
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You need to use sp_executesql (Dynamic SQL) to accomplish this task. =Something like this:
DECLARE
@.User nvarchar(20),
@.pwd nvarchar(20),
@.Sql nvarchar(200)
SELECT @.User =3D 'Mary', @.pwd =3D 'test'
SET @.Sql =3D 'CREATE LOGIN ''' + @.User + ''' WITH PASSWORD =3D ''' + =@.pwd + ''''
EXECUTE sp_executesql @.Sql
See Erland's excellent article about using Dynamic SQL.
Dynamic SQL - The Curse and Blessings of Dynamic SQL
http://www.sommarskog.se/dynamic_sql.html=20
-- Arnie Rowland, Ph.D.
Westwood Consulting, Inc
Most good judgment comes from experience. Most experience comes from bad judgment. - Anonymous
You can't help someone get up a hill without getting a little closer to =the top yourself.
- H. Norman Schwarzkopf
"Jim Johnson" <easytorememberemailaddress@.gmail.com> wrote in message =news:1166460727.281101.297550@.79g2000cws.googlegroups.com...
> Hi. Perhaps I am missing something obvious, but I am confused. I can
> add a SQL Server 2005 user with this command:
> > CREATE LOGIN 'AUser' WITH PASSWORD =3D 'hello', DEFAULT_DATABASE =3D =TEST1
> > However, I have 100 users to add, and I want to use TRANSACT-SQL to
> create the users automatically and pull their initial password info
> from a table. I use a cursor to do this, replacing the 'AUser' and
> 'hello' with variables, for example:
> > CREATE LOGIN @.usr WITH PASSWORD =3D @.pwd
> > I get an Incorrect syntax near '@.usr' error. Somehow this is not the
> correct datatype, I would imagine. I used this method with =sp_addlogin
> in SQL 2000 without a problem.
> > I've tried declaring @.usr as a varchar or nvarchar without success.
> > Please offer any suggestions.
> > Thank you.
>
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&
You need to use sp_executesql (Dynamic =SQL) to accomplish this task. Something like this:
DECLARE @.User nvarchar(20), @.pwd nvarchar(20), @.Sql nvarchar(200)
SELECT @.User ==3D 'Mary', @.pwd =3D 'test'
SET @.Sql =3D 'CREATE LOGIN ''' =+ @.User + ''' WITH PASSWORD =3D ''' + @.pwd + ''''
EXECUTE sp_executesql =@.Sql
See Erland's excellent article about =using Dynamic SQL.
Dynamic SQL - The Curse =and Blessings of Dynamic SQLhttp://www.sommarskog.se/dynamic_sql.html">http://www.sommarskog.=se/dynamic_sql.html -- Arnie Rowland, =Ph.D.Westwood Consulting, Inc
Most good judgment comes from =experience. Most experience comes from bad judgment. - Anonymous
You can't help someone get up a hill =without getting a little closer to the top yourself.- H. Norman Schwarzkopf
"Jim Johnson"
wrote in message news:1166460727.281101.297550@.79g2000cws.googlegroups.com=...> =Hi. Perhaps I am missing something obvious, but I am confused. I can> =add a SQL Server 2005 user with this command:> > CREATE LOGIN ='AUser' WITH PASSWORD =3D 'hello', DEFAULT_DATABASE =3D TEST1> > =However, I have 100 users to add, and I want to use TRANSACT-SQL to> create the =users automatically and pull their initial password info> from a =table. I use a cursor to do this, replacing the 'AUser' and> 'hello' with variables, for example:> > CREATE LOGIN @.usr WITH PASSWORD ==3D @.pwd> > I get an Incorrect syntax near '@.usr' error. Somehow this is not the> correct datatype, =I would imagine. I used this method with sp_addlogin> in SQL 2000 =without a problem.> > I've tried declaring @.usr as a varchar or =nvarchar without success.> > Please offer any suggestions.> => Thank you.>
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